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If the ball is a monopole, which is of course impossible then maybe there would be some difference, but as the ball must have both a North and South pole they will cancel... but...
Say the ball is falling N pole down wards towards the N pole of the Earth, the repulsion will tend to make the ball rotate until the N pole is upper most, The S pole being downward will now be attracted towards the earth causing it to accelerate at a phenomenal rate crashing into the Ice and sending huge plumes of crushed ice into the atmosphere and any glasses of gin and tonic which are in the vicinity...This will blot out the sun and we'll all freeze our nuts off.
Conversely it may make no difference whatsoever as the mean field around the ball is zero.
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Once the ball has rotated as you describe, the S pole will be slightly more strongly attracted than the N pole is repelled (since the N is farther away), so it should fall slightly faster. I have made NO calculations to determine how much faster, but I suspect that it would take very sensitive measurements to detect the change.
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Where is the moon at the time of the drop. As we know because of why there are high and low tides, the moon has gravitational pull on an object which will vary in relationship to the poles, equator, and what altitude at which the ball is dropped from. As we also know from the toilet flushing effect, the ball will try to rotate clockwise or counterclockwise depending on which hemisphere the drop is made. Just how did you make this "round magnet" in the first place? Was it first a magnetized square or rectangle and then shaped into a ball? Or do you have some way of "perfectly" magetizing something round so that the magnetic center is also the physical center? Careful now for that might approach a perpetual device, and we all know our wives won't let us bring that thing home. Another thought has to do with some locations on earth that have significant iron ore deposits that easily disturb any compass from indcating magnetic north (as opposed to "true north"). I hope this helps. Did we just confuse gravity with magnetism? Do I weigh more at the poles than I do at the equator? Weight does equal the effect of gravity therefore speed if dropped right? Or am I magetically held down on this planet.
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My friend be confirm that the gravity doesnt have magnet poles across the earth.Ovbiously earth has two poles north and south.But these poles dont have enough power to attract or repulse any pullable body.Just by compass we can define poles of earth , thats all.If it has powerful magnetism then many things even human being holding opposite poles magnet will float in atmosphere and make another world there.
So in my reading the magnet ball will drop as normal balls.
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The magnetized steel ball (a hard shape to make a magnet) will, like the earth, have magnetic poles, and will orient itself to the earth's field. This alone does not make any significant difference.
At the equator, 1) any falling steel ball is cutting many magnetic lens of force, so it seems like they should induce current in the interior, heating it, doing work and slowing the fall. The magnitized ball should have very slightly less current, as the existing magnetism puts the flux in a less freindly part of the hysterisis curve, nearer to saturation. 2) The magnetic poles cancel out in terms of attracting the magnetized ball, pulling it both North and South equally. For simplicity, we are talking about a magnetic equator or an earth whose magnetic and rotational poles are aligned.
At the magnetic pole, 3) the magnetic attraction on the magnetized ball will accelerate the fall more than gravity and more than an unmagnetized ball.
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i will argue that if the magnetization is very strong, and the height from which the balls are dropped is extremely high, a substancial difference in fall rates between the magnetized and non-magnetized balls will develop consistently. .....
The variation in fall rates should also exhibit differences between data taken near the equator and data take at the poles...
but if you think the variations in fall rates occur due to the strength or allignment on the Earths magnetic field, or gravity... you were tricked by the question.
the dominating factor will be the conductivity of the atmosphere through which the balls fall.
this problem is easier to understand,when you remember LENZ LAW.... which means the non-magnetized ball will fall more rapidly than the magnetized ball.
higher conductivityin the atmoshpere, and the greater altitude(and resulting higher velocity..... Results in a more pronounced magnetized ball lagtime will be.
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